# How do you find abs( 2 + 3i )?

$| 2 + 3 i | = \sqrt{13}$
$| a + b i | = \sqrt{{a}^{2} + {b}^{2}}$
Hence, $| 2 + 3 i | = \sqrt{{2}^{2} + {3}^{2}} = \sqrt{4 + 9} = \sqrt{13}$