Question

How do you find `abs( –2 + 6i )`?

Answer 1

`|-2+6i|=sqrt40`

Explanation:

Absolute value of a complex number `a+ib` is denoted as `|a+ib|`

and is given by `sqrt(a^2+b^2)`

Hence absolute value `|-2+6i|` is

`sqrt(2^2+6^2)=sqrt(4+36)=sqrt40`