How do you find $abs( –2 + 6i )$ ?

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Answer 1 · 2016-05-23T13:57:22

$|-2+6i|=sqrt40$

Absolute value of a complex number $a+ib$ is denoted as $|a+ib|$

and is given by $sqrt(a^2+b^2)$

Hence absolute value $|-2+6i|$ is

$sqrt(2^2+6^2)=sqrt(4+36)=sqrt40$

How do you find abs( –2 + 6i )abs( –2 + 6i )?