How do you find $abs( 2 − i )$ ?

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Answer 1 · 2016-08-23T21:58:09

$|2-i|=sqrt5$

The absolute value of complex number $a+bi$ is written as $|a+bi|$ and is equivalent to $sqrt(a^2+b^2)$ .

Hence $|2-i|$

= $sqrt(2^2+(-1)^2)$

= $sqrt(4+1)$

= $sqrt5$

How do you find abs( 2 − i )abs( 2 − i )?