How do you find $abs(3 + 2i )$ ?

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Answer 1 · 2016-05-24T06:10:52

$|3+2i|=sqrt13$

Absolute value of a complex number $a+ib$ is denoted as $|a+ib|$

and is given by $sqrt(a^2+b^2)$

Hence absolute value $|3+2i|$ is

$sqrt(3^2+2^2)=sqrt(9+4)=sqrt13$

How do you find abs(3 + 2i )abs(3 + 2i )?