How do you find $abs( -3 + 7i )$ ?

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Answer 1 · 2016-07-29T08:06:37

$|-3+7i|=sqrt58$

Absolute value of a complex number $a+bi$ is written as $|a+bi|$ and is equal to $sqrt(a^2+b^2)$

Hence absolute value of $-3+7i$ is

$|-3+7i|=sqrt((-3)^2+7^2)=sqrt(9+49)=sqrt58$

How do you find abs( -3 + 7i )abs( -3 + 7i )?