How do you find abs( -4sqrt3-4i )?

May 23, 2016

$| - 4 \sqrt{3} - 4 i | = 8$

Explanation:

Absolute value of a complex number $a + i b$ is denoted as $| a + i b |$

and is given by $\sqrt{{a}^{2} + {b}^{2}}$

Hence absolute value $| - 4 \sqrt{3} - 4 i |$ is

$\sqrt{{\left(4 \sqrt{3}\right)}^{2} + {4}^{2}} = \sqrt{48 + 16} = \sqrt{64} = 8$