How do you find $| 9 + 4 i |$ $abs( 9 + 4i )$ ?

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Answer 1 · 2016-06-03T06:47:46

$| 9 + 4 i | = \sqrt{97}$ $|9+4i|=sqrt97$

$| a + b i |$ $|a+bi|$ is the absolute value or modulas of complex number $a + b i$ $a+bi$

and is given by $\sqrt{a^{2} + b^{2}}$ $sqrt(a^2+b^2)$

Hence $| 9 + 4 i | = \sqrt{9^{2} + 4^{2}} = \sqrt{81 + 16} = \sqrt{97}$ $|9+4i|=sqrt(9^2+4^2)=sqrt(81+16)=sqrt97$

How do you find |9+4i|abs( 9 + 4i )?