How do you find #abs( 9 + 4i )#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Shwetank Mauria Jun 3, 2016 #|9+4i|=sqrt97# Explanation: #|a+bi|# is the absolute value or modulas of complex number #a+bi# and is given by #sqrt(a^2+b^2)# Hence #|9+4i|=sqrt(9^2+4^2)=sqrt(81+16)=sqrt97# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1780 views around the world You can reuse this answer Creative Commons License