Question

How do you find `abs( sqrt 5 + 2i sqrt2)`?

Answer 1

`|sqrt5+2sqrt2i|=sqrt13`

Explanation:

`|a+bi|=sqrt(a^2+b^2)`

Hence, `|sqrt5+2sqrt2i|`

= `sqrt((sqrt5)^2+(2sqrt2)^2)`

= `sqrt(5+8)`

= `sqrt13`