How do you find all additional roots given the roots 2+3i and $\sqrt{7}$ $sqrt7$ ?

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Answer 1 · 2017-02-14T16:15:33

$2 - 3 i$ $2-3i$ and $- \sqrt{7}$ $-sqrt(7)$

Complex roots always come in pairs. For example:
$\pm i$ $+-i$ , $1 \pm 4 i$ $1+-4i$ , $2 \pm 3 i$ $2+-3i$

If $x^{2} = 7$ $x^2 = 7$ ; $x$ $x$ can be positive or negative: $x = \pm \sqrt{7}$ $x=+-sqrt(7)$

How do you find all additional roots given the roots 2+3i and sqrt7√7sqrt7?