# How do you find all the complex roots of #x^3+6x^2+11x+6#?

##### 1 Answer

Jan 11, 2016

There are no complex roots.

#### Explanation:

Try to divide the polynomial, either through polynomial long division or synthetic division.

The factors you should try are

The first root I encountered was

This is easily factorable into

Thus, this cubic has three real roots,

graph{x^3+6x^2+11x+6 [-11.29, 8.71, -4, 6]}