How do you find all the measures of the angles in a triangle that have the ratio of 1:3:5?

1 Answer
Mar 6, 2017

If the given ratio is to be the ratio of the sides:
#color(white)("XXX")#No such triangle is possible.
If the given ratio is to be the ratio of the angles:
#color(white)("XXX")#The angles are #20^@, 60^@, and 100^@#

Explanation:

Case 1: ratio is ratio of lengths of sides
The length of the two shorter sides of a triangle must be greater than the length of the third side.

Case 2: ratio is ratio of angles
If the smallest angle is #x^@#
then the ratio #1:3:5# corresponds to angles #x^@, 3x^@, and 5x^@#

Since the sum of interior angles of a triangle is #180^@#
#color(white)("XXX")x+3x+5x=180#

#color(white)("XXX")rarr 9x=180#

#color(white)("XXX")rarr x=20#

and the angles are #20^@, 60^@, and 100^@#