How do you find all the real and complex roots of #x^2-3=0#?

1 Answer
Feb 13, 2016

Answer:

#x=+-sqrt3#

Explanation:

Solve the equation as you normally would.

Move the #3# to the right side of the equation.

#x^2=3#

Take the square root of both sides. Recall that the square root can be positive or negative.

#sqrt(x^2)=+-sqrt3#

#x=+-sqrt3#

These are the only two roots (both of which are real). We know the equation will only have two roots since the function's degree (largest exponent) is #2#.