# How do you find all the real and complex roots of x^2-3=0?

Feb 13, 2016

$x = \pm \sqrt{3}$

#### Explanation:

Solve the equation as you normally would.

Move the $3$ to the right side of the equation.

${x}^{2} = 3$

Take the square root of both sides. Recall that the square root can be positive or negative.

$\sqrt{{x}^{2}} = \pm \sqrt{3}$

$x = \pm \sqrt{3}$

These are the only two roots (both of which are real). We know the equation will only have two roots since the function's degree (largest exponent) is $2$.