How do you find all the real and complex roots of #x^3 + 4x^2 + 3x = 0#?

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Abhi Share
Mar 20, 2018

#x^3+4x^2+4x=0#
#x(x^2+4x+3)=0#
implies x=0 and #x^2 + 4x+3=0#
thus we got one root and the other two roots are obtained by solving #x^2 + 4x+3=0#
#(x+1)(x+3)=0#
implies x=-1,x=-3
hence the roots are x=0,-1,-3

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