Question

How do you find all the real and complex roots of `x(x^2 - 4)(x^2 + 16) = 0`?

Answer 1

`x=0,+-2,+-4i`

Explanation:

`x(x^2-4)(x^2+16)=0`
`x(x+2)(x-2)(x+4i)(x-4i)=0`
`:.` `x=0,+-2,+-4i`