Question

How do you find all the values that make the expression undefined: `(3x^2 - 3)/(6x - 6)`?

Answer 1

For this expression to be undefined, your denominator cannot be zero, as it's an indetermination when you have something divided by zero.

Thus, this expression becomes undefined when `6x-6=0`, thus, when `x=1`.

In this case, by the way, we'd have an interesting topic in calculus: `0/0`, but that's not the case for now.

So, your answer: this function becomes undefined only when `x=1`.

Besides, when `x=+-1`, your numerator becomes zero, but when `x=-1`, then your numerator would be `-12`, and thus, you function, `0/(-12)=0`, and zero is a defined value.