# How do you find all the zeros of #f(x) = {x+1/4}^2(x - 1)^5#?

##### 1 Answer

Aug 13, 2016

#### Answer:

Observe the linear factors to see that

#-1/4# with multiplicity#2#

#1# with multiplicity#5#

#### Explanation:

Note that linear factors correspond to zeros. The product of several factors is zeros if and only if at least one of the factors is zero.

So we can observe that

#-1/4# with multiplicity#2#

#1# with multiplicity#5#

Here's a graph of

graph{5(x+1/4)^2(x-1)^5 [-0.62, 1.88, -0.54, 0.71]}