# How do you find all the zeros of f(x) = x^2 + 5x +6?

Aug 5, 2016

The zeros of $f \left(x\right)$ are $x = - 2$ and $x = - 3$

#### Explanation:

Note that $2 + 3 = 5$ and $2 \times 3 = 6$

So we find:

$f \left(x\right) = {x}^{2} + 5 x + 6 = \left(x + 2\right) \left(x + 3\right)$

Hence the zeros of $f \left(x\right)$ are $x = - 2$ and $x = - 3$