# How do you find all the zeros of f(x) = x^2 - 8x + 12?

Apr 5, 2016

x = 2 , x = 6

#### Explanation:

Zeros are the values of x that make the function equal zero.

ie ${x}^{2} - 8 x + 12 = 0$

Factor the quadratic and solve for x.

$\Rightarrow {x}^{2} - 8 x + 12 = \left(x - 2\right) \left(x - 6\right) = 0$

x - 2 = 0 → x = 2

x - 6 = 0 → x = 6