How do you find all the zeros of #f(x) = x^2 - 8x + 12#?
1 Answer
Apr 5, 2016
x = 2 , x = 6
Explanation:
Zeros are the values of x that make the function equal zero.
ie
# x^2 - 8x + 12 = 0 # Factor the quadratic and solve for x.
#rArr x^2 - 8x + 12 = (x - 2 )(x - 6 ) = 0 # x - 2 = 0 → x = 2
x - 6 = 0 → x = 6
