How do you find all the zeros of #f(x)=(x+3)^2(x-1)#?

1 Answer
Apr 9, 2016

Answer:

#x= 3#, multiplicity of two and

# x= 1# , multiplicity of one

Explanation:

Set the equation equal to zero and solve for #x# as follow

#f(x) = (x+3)^2(x-1)#

#0= (x+3)(x+3) ; " " " " " " x-1= 0#

#0=x+3 " " " " " " " " " x= 1#

#x= -3#

The zero are #x= 3# multiplicity of two and #x= 1# multiplicity of one.