How do you find all the zeros of #f(x) = x^3 - 6x^2 - x + 6 #?
1 Answer
Mar 23, 2016
Factor by grouping to find zeros:
Explanation:
Factor by grouping:
#x^3-6x^2-x+6#
#=(x^3-6x^2)-(x-6)#
#=x^2(x-6)-1(x-6)#
#=(x^2-1)(x-6)#
#=(x-1)(x+1)(x-6)#
So the zeros are:
#{ (x=1), (x=-1), (x=6) :}#
