# How do you find all the zeros of f(x)=x^3-8x^2+15x?

$x = 0 , x = 5 , x = 3$
$x \left({x}^{2} - 8 x + 15\right) = 0$
$x \left(x - 5\right) \left(x - 3\right) = 0$
$x = 0 , x - 5 = 0 , x - 3 = 0$
$x = 0 , x = 5 , x = 3$