Question

How do you find all the zeros of `f(x)=x^3-8x^2+15x`?

Answer 1

`x=0,x=5,x=3`

Explanation:

`x(x^2-8x+15)=0`
`x(x-5)(x-3)=0`
`x=0,x-5=0,x-3=0`
`x=0,x=5,x=3`