Question

How do you find all the zeros of `f(x) = x^3 – 9x^2 + 20x` with its multiplicities?

Answer 1

`f(x)` has zeros `0, 4, 5`

Explanation:

Note that `4+5=9` and `4*5=20`

So we find:

`f(x) = x^3-9x^2+20x = x(x-4)(x-5)`

Hence zeros: `0, 4, 5`