# How do you find all the zeros of f(x) = x^3 – 9x^2 + 20x with its multiplicities?

Aug 19, 2016

$f \left(x\right)$ has zeros $0 , 4 , 5$

#### Explanation:

Note that $4 + 5 = 9$ and $4 \cdot 5 = 20$

So we find:

$f \left(x\right) = {x}^{3} - 9 {x}^{2} + 20 x = x \left(x - 4\right) \left(x - 5\right)$

Hence zeros: $0 , 4 , 5$