How do you find all the zeros of F(x) = x^4 - 16x^2?

Feb 27, 2016

Answer:

Zeros: 0 multiplicity 2, ±4

Explanation:

$\left[1\right] \text{ } f \left(x\right) = {x}^{4} - 16 {x}^{2}$

Factor.

$\left[2\right] \text{ } f \left(x\right) = x \cdot x \cdot \left({x}^{2} - 16\right)$

$\left[3\right] \text{ } f \left(x\right) = x \cdot x \cdot \left(x + 4\right) \cdot \left(x - 4\right)$

Find all values of $x$ that will make $f \left(x\right)$ zero.

Zeros: 0 multiplicity 2, -4, 4