How do you find all the zeros of #g(x) = 2x^3 + x^2 - 6x - 3#?

1 Answer
Rene
Mar 13, 2016

#x=sqrt(3)# and #x=-1/2#

Explanation:

First of all, let us factorize your equation #2x^3+x^2−6x−3#. We can display the equation in the following format:

#x^2(2x+1)-3(2x+1)# ========> #(x^2-3)(2x+1)#

Now we can find the zeros:

#x=sqrt(3)# and #x=-1/2#

If there are any further questions, let me know

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