# How do you find all the zeros of #P(x) = 6x^3 − 13x^2 + 14x − 2# with 1+i as a root?

##### 1 Answer

Jun 12, 2016

#### Answer:

All the zeros of the given polynomial

are

#### Explanation:

Let us remember that the complex roots occur in conjugate pairs. Now one such root is given to be

Since

Let the 3rd root be

Now, by Vieta's Rule,

From the 1st equation (eqn.), we get

We verify that this value of

Hence the roots