How do you find all the zeros of #P(x) = x^4 - 4x^3 + 3x^2 + 4x - 4# where 2 is a zero?
The zeros are
The sum of the coefficients in P(x) is 0, 1 is a zero. The sum of the coefficients in
Let P(x) = #(x-1)(x+1)(x-2)(bx+c).
comparing coefficients of
So, P(x) = #(x-1)(x+1)(x-2)(x-2). 2 is a double root.