# How do you find all the zeros of #x^3-12x^2+12x+80# with #-2# as a zero?

##### 1 Answer

Jul 14, 2016

Zeros: -2, 10, 4.

#### Explanation:

Since we are told that

#x^3-12x^2+12x+80 = (x+2)(x^2-14x+40)#

To factor the remaining quadratic, we can find a pair of factors of

#x^2-14x+40 = (x-10)(x-4)#

So the other two zeros are