Question

How do you find all the zeros of `y=x^2-3x-4` with its multiplicities?

Answer 1

This quadratic has zeros `x=4` and `x=-1`, both with multiplicity `1`.

Explanation:

`y=x^2-3x-4=(x-4)(x+1)`

Hence zeros `x=4` and `x=-1`, both with multiplicity `1`.