# How do you find all the zeros of y = ( x -3)^4 (2x+4) (3x-2)?

Jun 22, 2018

To find the zeroes, set each binomial equal to 0.

#### Explanation:

Once we set them up like this, ...

${\left(x - 3\right)}^{4} = 0$
$2 x + 4 = 0$
$3 x - 2 = 0$

…we can simplify them.

$\sqrt[4]{{\left(x - 3\right)}^{4}} = \sqrt[4]{0}$
$x - 3 = 0$
$x = 3$

$2 x = - 4$
$x = - \frac{4}{2} = - 2$

$3 x = 2$
$x = \frac{2}{3}$

Zeroes: $x = 3 , - 2 , \frac{2}{3}$