# How do you find all values of k such that #2x^2-3x+5k=0# has two solutions?

##### 1 Answer

Feb 16, 2017

#### Answer:

For

For

#### Explanation:

The discriminant here is:

Assume

For the equation to have two roots (real and complex) the discriminant must not equal zero.

If the roots are to be real only the discriminant must be greater than zero.