How do you find all zeros for (x + 1)(x - 4)(x^2 - 7)?

Apr 17, 2018

$x = - 1 , x = 4 , x = \pm \sqrt{7}$

Explanation:

$\text{to find the zeros equate the product of factors to zero}$

$\Rightarrow \left(x + 1\right) \left(x - 4\right) \left({x}^{2} - 7\right) = 0$

$\text{equate each factor to zero and solve for x}$

$x + 1 = 0 \Rightarrow x = - 1$

$x - 4 = 0 \Rightarrow x = 4$

${x}^{2} - 7 = 0 \Rightarrow {x}^{2} = 7 \Rightarrow x = \pm \sqrt{7}$