How do you find all zeros of #f(x)=49-x^2#?

1 Answer
Mar 1, 2017

Answer:

x= -7, x=7

Explanation:

Set 49- #x^2# = 0 and factor

You'll get (x-7)(x+7)
You can check if you factored correctly by distributing or using F.O.I.L

Now you have to set (x-7)(x+7) equal to 0 and solve for x.

Treat them as two separate equations
So...

(x-7) = 0 (x+7) = 0
Once you solve for x you'll find that x is equal to 7 and -7 and these are your zeros.