# How do you find all zeros of the function 2x^3-3x^2-16x+10?

I will graph this as a function, $f \left(x\right) = 2 {x}^{3} - 3 {x}^{2} - 16 x + 10$.
Notice that -2.5 seems to be the "nicest" zero. That means 2x+5 is a factor. If you do long division on the original polynomial by 2x+5, you will get ${x}^{2} - 4 x + 2$. You can solve that quadratic with the quadratic formula to get: $2 + \sqrt{2} , 2 - \sqrt{2}$.