How do you find all zeros of the function #2x^3-3x^2-16x+10#?

1 Answer
Mar 29, 2016


I will graph this as a function, #f(x) = 2x^3-3x^ screenshot 6


Notice that -2.5 seems to be the "nicest" zero. That means 2x+5 is a factor. If you do long division on the original polynomial by 2x+5, you will get #x^2-4x+2#. You can solve that quadratic with the quadratic formula to get: #2+sqrt(2), 2-sqrt(2)#.

my screenshot 7