How do you find all zeros of the function #f(x)=2(x+9)^2 (x-9)^3#? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Mia Nov 18, 2016 #" " x=-9" " Or " " x=9# Explanation: #f(x) = 0# #" "# #2(x+9)^2(x-9)^3=0# #" "# #(x+9)^2=0" "rArr x+9=0" "rArr x=-9# #" "# Or #" "# #(x-9)^3=0" "rArrx-9=0" "rArrx=9# #" "# #" "# Hence,#" " x=-9" " Or " " x=9# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 1165 views around the world You can reuse this answer Creative Commons License