# How do you find all zeros of the function f(x)=-2x^2+2x+4?

$f \left(x\right)$ has zeros $2$ and $- 1$
$f \left(x\right) = - 2 {x}^{2} + 2 x + 4 = - 2 \left({x}^{2} - x - 2\right) = - 2 \left(x - 2\right) \left(x + 1\right)$
Hence the zeros of $f \left(x\right)$ are $x = 2$ and $x = - 1$