# How do you find all zeros of the function x² – 14x – 32 = 0?

${x}^{2} - 16 x + 2 x - 32 = 0$
Or,$x \left(x - 16\right) + 2 \left(x - 16\right) = 0$
Or,$\left(x - 16\right) \left(x + 2\right) = 0$
$\therefore x = 16 \mathmr{and} - 2$