How do you find all zeros with multiplicities of #f(x)=3x^4-14x^2-5#?

1 Answer
Feb 13, 2017

Answer:

#x = +-sqrt(3)/3i#

#x = +-sqrt(5)#

Explanation:

#f(x) = 3x^4-14x^2-5#

#color(white)(f(x)) = (3x^4-15x^2)+(x^2-5)#

#color(white)(f(x)) = 3x^2(x^2-5)+1(x^2-5)#

#color(white)(f(x)) = (3x^2+1)(x^2-5)#

#color(white)(f(x)) = ((sqrt(3)x)^2-i^2)(x^2-(sqrt(5))^2)#

#color(white)(f(x)) = (sqrt(3)x-i)(sqrt(3)x+i)(x-sqrt(5))(x+sqrt(5))#

Hence zeros:

#x = +-i/sqrt(3) = +-sqrt(3)/3i#

#x = +-sqrt(5)#