# How do you find all zeros with multiplicities of #f(x)=x^3-2x^2-5x+6#?

##### 1 Answer

Aug 22, 2017

#### Answer:

The zeros of

#### Explanation:

Given:

#f(x) = x^3-2x^2-5x+6#

Note that the sum of the coefficients is

#1-2-5+6 = 0#

Hence we find

#x^3-2x^2-5x+6 = (x-1)(x^2-x-6)#

To factor the remaining quadratic find a pair of factors of

#x^2-x-6 = (x-3)(x+2)#

So the zeros of