# How do you find #(d^2y)/(dx^2)# given #x^2+y^2=13#?

##### 1 Answer

Dec 14, 2016

See below.

#### Explanation:

Given

Therefore,

# =( -y+x(-x/y))/y^2 * y/y#

# = (-y^2-x^2)/y^3#

# = (-13)/y^3# .