Question

How do you find derivative of `f(x)=(x^2+4x+3)/(sqrtx)`?

Answer 1

In this way:

`y'=((2x+4)*sqrtx-(x^2+4x+3)*1/(2sqrtx))/(sqrtx)^2=`

`=(((2x+4)sqrtx*2sqrtx-x^2-4x-3)/(2sqrtx))/x=`

`=((2x+4)*2x-x^2-4x-3)/(2xsqrtx)=`

`=(4x^2+8x-x^2-4x-3)/(2xsqrtx)=(3x^2+4x-3)/(2xsqrtx)`.