# How do you find domain and range for  f(x) = (x^2 - 16) / (x^2 - 25)?

Domain = $x \in \mathbb{R} : x \ne - 5 , 5$
Range = $x \in \mathbb{R} : x \ne 1$
First solve for domain which for inverse functions is equal to all real numbers except for when the denominator is equal to zero (so solve ${x}^{2} - 25 = 0 \rightarrow x = - 5 , 5$ so the domain is equal to all real numbers except -5 and 5