How do you find dy/dx by implicit differentiation for 1+x = sin(xy^2)?
1 Answer
May 11, 2018
Explanation:
Implicitly differentiate the Left-Hand Side with respect to
d/(dx)[1+x]=1 by the power rule
The right-hand side is slightly trickier...
color(white)(l)d/(dx)[sin(x*y^2)]
=cos(x*y^2)*d/(dx)[x*y^2]
=cos(x*y^2)*(y^2+2x*y*(dy)/(dx))
by the chain rule along with the cosine rule.
Hence
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