# How do you find #dy/dx# by implicit differentiation of #x^3+y^3=8#?

##### 1 Answer

Feb 13, 2017

#### Explanation:

We have:

# x^3+y^3=8 #

Differentiate wrt

# 3x^2 + d/dxy^3=0 #

# :. 3x^2 + dy/dxd/dyy^3=0 #

# :. 3x^2 + dy/dx(3y^2)=0 #

# :. x^2 + y^2dy/dx=0 #

# :. dy/dx=-x^2/y^2 #