Question

How do you find `(dy)/(dx)` given `x^2y^2=1`?

Answer 1

Please see the explanation.

Explanation:

Use the product rule:

`2xy^2 + 2x^2y(dy/dx) = 0`

`2x^2y(dy/dx) = -2xy^2`

`dy/dx = (-2xy^2)/(2x^2y)`

`dy/dx = -y/(x)`