How do you find #(dy)/(dx)# given #x=sqrt(tan(y^2))#?
1 Answer
Nov 9, 2016
Explanation:
# x = sqrt(tan(y^2) #
# :. x^2 = tan(y^2) #
Differentiating implicitly wrt
# :. 2x = sec^2(y^2) (2y)dy/dx #
# :. x = ysec^2(y^2) dy/dx #
# :. dy/dx = x / (ysec^2(y^2))#
