# How do you find #(dy)/(dx)# given #xcosy+y=x^3#?

##### 1 Answer

Oct 26, 2016

#### Explanation:

differentiate

#color(blue)"implicitly with respect to x"#

#• "Use the "color(blue)"product rule"# on the term xcosy

#rArrx(-siny).dy/dx+cosy.1+1.dy/dx=3x^2#

#rArrdy/dx(-xsiny+1)=3x^2-cosy#

#rArrdy/dx=(3x^2-cosy)/(1-xsiny)#