How do you find equation of line through point (5, -2) parallel to line 3y+7=-8?

Jun 9, 2016

$y = - 2$

Explanation:

Subtract $\textcolor{b l u e}{7}$ from both sides

$\textcolor{b r o w n}{3 y + 7 = - 8 \text{ "->" } 3 y + 7 \textcolor{b l u e}{- 7} = - 8 \textcolor{b l u e}{- 7}}$

$3 y = - 15$

Divide both sides by 3

$\frac{3}{3} y = - \frac{15}{3}$

$1 \times y = - 5$

$y = - 5 \text{ "larr" Parallel to the x-axis}$

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$y = - 2$ is parallel to the other equation and passes through the point (5,-2).