# How do you find #(f^-1)'(a)# if #f(x)= x/sqrt{x-3}# and a = 4?

##### 1 Answer

Oct 6, 2016

The function is not bijective, So, the bi-valued inverse is not differentiable. See the explanation..

#### Explanation:

y = f(x) is real for x >=3.

Inversely, bi-valued

However, assigning y = 4, x = 4 or 12.for the two inverse forms.

Both are admissible....

The inverse is not unique for the given y = a = 4. The inverse is not

differentiable.