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How do you find f'(4) using the limit definition given #f(x) = x+3#?

1 Answer

Sep 18, 2017

see below

Explanation:

#f'(x)=Lim_(hrarr0)(f(x+h)-f(x))/h#

in this case

#f(x)=x+3#

applying the definition

#f'(x)=Lim_(hrarr0)(cancel(x+3)+h-cancel((x+3)))/h#

#f'(x)=Lim_(hrarr0)h/h=Lim_(hrarr0)1=1#

#f'(x)=1:.f'(4)=1#

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