# How do you find f(x) and g(x) such that h(x)=(fog)(x) and h(x)=(8-4x)^2?

$\left(f \circ g\right) \left(x\right)$ is equivalent to $f \left(g \left(x\right)\right)$. So, $g \left(x\right)$ is within $f \left(x\right)$. So, $g \left(x\right) = 8 - 4 x$ and $f \left(x\right) = {x}^{2}$.