Question

How do you find f(x) and g(x) such that `h(x)=(fog)(x)` and `h(x)=(8-4x)^2`?

Answer 1

`(f @g)(x)` is equivalent to `f(g(x))`. So, `g(x)` is within `f(x)`. So, `g(x) = 8 - 4x` and `f(x) = x^2`.

Hopefully this helps!